23405115042031 has 2 divisors, whose sum is σ = 23405115042032. Its totient is φ = 23405115042030.

The previous prime is 23405115041993. The next prime is 23405115042103. The reversal of 23405115042031 is 13024051150432.

Together with next prime (23405115042103) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 23405115042031 - 2⁹ = 23405115041519 is a prime.

It is a super-2 number, since 2×23405115042031² (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 23405115041984 and 23405115042002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23405115043031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11702557521015 + 11702557521016.

It is an arithmetic number, because the mean of its divisors is an integer number (11702557521016).

Almost surely, 2^{23405115042031} is an apocalyptic number.

23405115042031 is a deficient number, since it is larger than the sum of its proper divisors (1).

23405115042031 is an equidigital number, since it uses as much as digits as its factorization.

23405115042031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 23405115042031 its reverse (13024051150432), we get a palindrome (36429166192463).

The spelling of 23405115042031 in words is "twenty-three trillion, four hundred five billion, one hundred fifteen million, forty-two thousand, thirty-one".