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2341251439993 is a prime number
BaseRepresentation
bin100010000100011101011…
…101011101110101111001
322021211011211122011011001
4202010131131131311321
5301324340332034433
64551320035405001
7331102251612334
oct42043535356571
98254154564131
102341251439993
11822a12446554
12319900453761
1313ca187aa66b
148146247d61b
1540d7be7057d
hex2211d75dd79

2341251439993 has 2 divisors, whose sum is σ = 2341251439994. Its totient is φ = 2341251439992.

The previous prime is 2341251439979. The next prime is 2341251440051. The reversal of 2341251439993 is 3999341521432.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2175970163689 + 165281276304 = 1475117^2 + 406548^2 .

It is a cyclic number.

It is not a de Polignac number, because 2341251439993 - 225 = 2341217885561 is a prime.

It is not a weakly prime, because it can be changed into another prime (2341251439393) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1170625719996 + 1170625719997.

It is an arithmetic number, because the mean of its divisors is an integer number (1170625719997).

Almost surely, 22341251439993 is an apocalyptic number.

It is an amenable number.

2341251439993 is a deficient number, since it is larger than the sum of its proper divisors (1).

2341251439993 is an equidigital number, since it uses as much as digits as its factorization.

2341251439993 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6298560, while the sum is 55.

The spelling of 2341251439993 in words is "two trillion, three hundred forty-one billion, two hundred fifty-one million, four hundred thirty-nine thousand, nine hundred ninety-three".