Base | Representation |
---|---|
bin | 10101110011100101… |
… | …011110011000111001 |
3 | 2020102202122110212011 |
4 | 111303211132120321 |
5 | 340422443240441 |
6 | 14431204045521 |
7 | 1456136025433 |
oct | 256345363071 |
9 | 66382573764 |
10 | 23414040121 |
11 | 9a2568498a |
12 | 46553938a1 |
13 | 2291aa8214 |
14 | 11c18a9653 |
15 | 920848581 |
hex | 57395e639 |
23414040121 has 2 divisors, whose sum is σ = 23414040122. Its totient is φ = 23414040120.
The previous prime is 23414040113. The next prime is 23414040131. The reversal of 23414040121 is 12104041432.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 18781332025 + 4632708096 = 137045^2 + 68064^2 .
It is a cyclic number.
It is not a de Polignac number, because 23414040121 - 23 = 23414040113 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 23414040092 and 23414040101.
It is not a weakly prime, because it can be changed into another prime (23414040131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11707020060 + 11707020061.
It is an arithmetic number, because the mean of its divisors is an integer number (11707020061).
Almost surely, 223414040121 is an apocalyptic number.
It is an amenable number.
23414040121 is a deficient number, since it is larger than the sum of its proper divisors (1).
23414040121 is an equidigital number, since it uses as much as digits as its factorization.
23414040121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 22.
Adding to 23414040121 its reverse (12104041432), we get a palindrome (35518081553).
The spelling of 23414040121 in words is "twenty-three billion, four hundred fourteen million, forty thousand, one hundred twenty-one".
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