Base | Representation |
---|---|
bin | 110101001111010010010101… |
… | …110010001010010011000111 |
3 | 1010201001020012112111012020211 |
4 | 311033102111302022103013 |
5 | 221142230423204011203 |
6 | 2145553342432340251 |
7 | 100214362461653524 |
oct | 6517222562122307 |
9 | 1121036175435224 |
10 | 234146950063303 |
11 | 68674189126582 |
12 | 223172b79a4687 |
13 | a085c68c29124 |
14 | 41b6ab69ba14b |
15 | 1c10a75c97c6d |
hex | d4f495c8a4c7 |
234146950063303 has 2 divisors, whose sum is σ = 234146950063304. Its totient is φ = 234146950063302.
The previous prime is 234146950063297. The next prime is 234146950063339. The reversal of 234146950063303 is 303360059641432.
234146950063303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 234146950063303 - 233 = 234138360128711 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (234146950064303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 117073475031651 + 117073475031652.
It is an arithmetic number, because the mean of its divisors is an integer number (117073475031652).
Almost surely, 2234146950063303 is an apocalyptic number.
234146950063303 is a deficient number, since it is larger than the sum of its proper divisors (1).
234146950063303 is an equidigital number, since it uses as much as digits as its factorization.
234146950063303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4199040, while the sum is 49.
The spelling of 234146950063303 in words is "two hundred thirty-four trillion, one hundred forty-six billion, nine hundred fifty million, sixty-three thousand, three hundred three".
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