Base | Representation |
---|---|
bin | 1010101001101001011001… |
… | …11111000101110001000011 |
3 | 10001221001020111021222111121 |
4 | 11110310230333011301003 |
5 | 11032213120104320113 |
6 | 121451320031453111 |
7 | 4635061311066043 |
oct | 524645477056103 |
9 | 101831214258447 |
10 | 23421211401283 |
11 | 750a975278913 |
12 | 2763230387197 |
13 | 100b7c2ab3697 |
14 | 5ad842459723 |
15 | 2a938d27ce8d |
hex | 154d2cfc5c43 |
23421211401283 has 2 divisors, whose sum is σ = 23421211401284. Its totient is φ = 23421211401282.
The previous prime is 23421211401277. The next prime is 23421211401407. The reversal of 23421211401283 is 38210411212432.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23421211401283 - 25 = 23421211401251 is a prime.
It is a super-3 number, since 3×234212114012833 (a number of 41 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (23421211441283) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11710605700641 + 11710605700642.
It is an arithmetic number, because the mean of its divisors is an integer number (11710605700642).
Almost surely, 223421211401283 is an apocalyptic number.
23421211401283 is a deficient number, since it is larger than the sum of its proper divisors (1).
23421211401283 is an equidigital number, since it uses as much as digits as its factorization.
23421211401283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18432, while the sum is 34.
The spelling of 23421211401283 in words is "twenty-three trillion, four hundred twenty-one billion, two hundred eleven million, four hundred one thousand, two hundred eighty-three".
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