Base | Representation |
---|---|
bin | 110101010001101110000000… |
… | …110001111101011001111111 |
3 | 1010201122012122121020120110222 |
4 | 311101232000301331121333 |
5 | 221203000234430213003 |
6 | 2150202225010051555 |
7 | 100232430603001316 |
oct | 6521560061753177 |
9 | 1121565577216428 |
10 | 234314101413503 |
11 | 68729063767a11 |
12 | 22343786579bbb |
13 | a0989569512c7 |
14 | 41c0c121a727d |
15 | 1c150aa498c38 |
hex | d51b80c7d67f |
234314101413503 has 2 divisors, whose sum is σ = 234314101413504. Its totient is φ = 234314101413502.
The previous prime is 234314101413419. The next prime is 234314101413517. The reversal of 234314101413503 is 305314101413432.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 234314101413503 - 212 = 234314101409407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (234314101413803) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 117157050706751 + 117157050706752.
It is an arithmetic number, because the mean of its divisors is an integer number (117157050706752).
Almost surely, 2234314101413503 is an apocalyptic number.
234314101413503 is a deficient number, since it is larger than the sum of its proper divisors (1).
234314101413503 is an equidigital number, since it uses as much as digits as its factorization.
234314101413503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51840, while the sum is 35.
Adding to 234314101413503 its reverse (305314101413432), we get a palindrome (539628202826935).
The spelling of 234314101413503 in words is "two hundred thirty-four trillion, three hundred fourteen billion, one hundred one million, four hundred thirteen thousand, five hundred three".
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