Base | Representation |
---|---|
bin | 1101101000111010110… |
… | …0000110110111101011 |
3 | 211101211022111010022102 |
4 | 3122032230012313223 |
5 | 12314342433124011 |
6 | 255351321044015 |
7 | 22633502335502 |
oct | 3321654066753 |
9 | 741738433272 |
10 | 234322161131 |
11 | 90414829923 |
12 | 394b602660b |
13 | 19133c92766 |
14 | b4ac581839 |
15 | 616675d73b |
hex | 368eb06deb |
234322161131 has 2 divisors, whose sum is σ = 234322161132. Its totient is φ = 234322161130.
The previous prime is 234322161089. The next prime is 234322161133. The reversal of 234322161131 is 131161223432.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 234322161131 - 26 = 234322161067 is a prime.
It is a super-2 number, since 2×2343221611312 (a number of 24 digits) contains 22 as substring.
Together with 234322161133, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 234322161094 and 234322161103.
It is not a weakly prime, because it can be changed into another prime (234322161133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 117161080565 + 117161080566.
It is an arithmetic number, because the mean of its divisors is an integer number (117161080566).
Almost surely, 2234322161131 is an apocalyptic number.
234322161131 is a deficient number, since it is larger than the sum of its proper divisors (1).
234322161131 is an equidigital number, since it uses as much as digits as its factorization.
234322161131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5184, while the sum is 29.
Adding to 234322161131 its reverse (131161223432), we get a palindrome (365483384563).
The spelling of 234322161131 in words is "two hundred thirty-four billion, three hundred twenty-two million, one hundred sixty-one thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •