Base | Representation |
---|---|
bin | 1010101001111110011101… |
… | …00000000011111111011011 |
3 | 10001222010101222200201100202 |
4 | 11110333032200003333123 |
5 | 11032404240321024011 |
6 | 121500425203452415 |
7 | 4635641320042403 |
oct | 524771640037733 |
9 | 101863358621322 |
10 | 23432511111131 |
11 | 75147437020a1 |
12 | 276546468710b |
13 | 100c8a3b36a25 |
14 | 5b01d5065803 |
15 | 2a98002c023b |
hex | 154fce803fdb |
23432511111131 has 2 divisors, whose sum is σ = 23432511111132. Its totient is φ = 23432511111130.
The previous prime is 23432511111059. The next prime is 23432511111187. The reversal of 23432511111131 is 13111111523432.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 23432511111131 - 234 = 23415331241947 is a prime.
It is a super-2 number, since 2×234325111111312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 23432511111094 and 23432511111103.
It is not a weakly prime, because it can be changed into another prime (23432511111731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11716255555565 + 11716255555566.
It is an arithmetic number, because the mean of its divisors is an integer number (11716255555566).
Almost surely, 223432511111131 is an apocalyptic number.
23432511111131 is a deficient number, since it is larger than the sum of its proper divisors (1).
23432511111131 is an equidigital number, since it uses as much as digits as its factorization.
23432511111131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2160, while the sum is 29.
Adding to 23432511111131 its reverse (13111111523432), we get a palindrome (36543622634563).
The spelling of 23432511111131 in words is "twenty-three trillion, four hundred thirty-two billion, five hundred eleven million, one hundred eleven thousand, one hundred thirty-one".
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