Base | Representation |
---|---|
bin | 1010101001111111110100… |
… | …00001010010101000011101 |
3 | 10001222012021212120012211000 |
4 | 11110333322001102220131 |
5 | 11032412234224222031 |
6 | 121501025445020513 |
7 | 4635665364046263 |
oct | 524777201225035 |
9 | 101865255505730 |
10 | 23433241242141 |
11 | 7514a88861355 |
12 | 27656290b4739 |
13 | 100c98c195903 |
14 | 5b0264004433 |
15 | 2a98444453e6 |
hex | 154ffa052a1d |
23433241242141 has 16 divisors (see below), whose sum is σ = 35835781112320. Its totient is φ = 15118220155680.
The previous prime is 23433241242139. The next prime is 23433241242149. The reversal of 23433241242141 is 14124214233432.
23433241242141 is a `hidden beast` number, since 2 + 3 + 4 + 33 + 241 + 242 + 141 = 666.
It is not a de Polignac number, because 23433241242141 - 21 = 23433241242139 is a prime.
It is a super-2 number, since 2×234332412421412 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 23433241242096 and 23433241242105.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23433241242149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 13998351160 + ... + 13998352833.
It is an arithmetic number, because the mean of its divisors is an integer number (2239736319520).
Almost surely, 223433241242141 is an apocalyptic number.
It is an amenable number.
23433241242141 is a deficient number, since it is larger than the sum of its proper divisors (12402539870179).
23433241242141 is a wasteful number, since it uses less digits than its factorization.
23433241242141 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 27996704033 (or 27996704027 counting only the distinct ones).
The product of its digits is 110592, while the sum is 36.
Adding to 23433241242141 its reverse (14124214233432), we get a palindrome (37557455475573).
The spelling of 23433241242141 in words is "twenty-three trillion, four hundred thirty-three billion, two hundred forty-one million, two hundred forty-two thousand, one hundred forty-one".
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