Base | Representation |
---|---|
bin | 1101101000111111000… |
… | …1010111000000000101 |
3 | 211101212120122102221011 |
4 | 3122033301113000011 |
5 | 12314412110041031 |
6 | 255353210122221 |
7 | 22634112545602 |
oct | 3321761270005 |
9 | 741776572834 |
10 | 234340315141 |
11 | 90423aa9239 |
12 | 39500120371 |
13 | 1913797a88a |
14 | b4b0b496a9 |
15 | 61681476b1 |
hex | 368fc57005 |
234340315141 has 2 divisors, whose sum is σ = 234340315142. Its totient is φ = 234340315140.
The previous prime is 234340315133. The next prime is 234340315151. The reversal of 234340315141 is 141513043432.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 193669526241 + 40670788900 = 440079^2 + 201670^2 .
It is a cyclic number.
It is not a de Polignac number, because 234340315141 - 23 = 234340315133 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (234340315151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 117170157570 + 117170157571.
It is an arithmetic number, because the mean of its divisors is an integer number (117170157571).
Almost surely, 2234340315141 is an apocalyptic number.
It is an amenable number.
234340315141 is a deficient number, since it is larger than the sum of its proper divisors (1).
234340315141 is an equidigital number, since it uses as much as digits as its factorization.
234340315141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 234340315141 its reverse (141513043432), we get a palindrome (375853358573).
The spelling of 234340315141 in words is "two hundred thirty-four billion, three hundred forty million, three hundred fifteen thousand, one hundred forty-one".
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