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23440211411 = 90725843673
BaseRepresentation
bin10101110101001001…
…010011110111010011
32020111120220010010012
4111311021103313103
5341001143231121
614433541025135
71456604336531
oct256511236723
966446803105
1023440211411
119a3942a851
1246620b51ab
13229733c5a6
1411c515d151
15922cb7c5b
hex575253dd3

23440211411 has 4 divisors (see below), whose sum is σ = 23466055992. Its totient is φ = 23414366832.

The previous prime is 23440211369. The next prime is 23440211413. The reversal of 23440211411 is 11411204432.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-23440211411 is a prime.

It is a super-2 number, since 2×234402114112 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (23440211413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12920930 + ... + 12922743.

It is an arithmetic number, because the mean of its divisors is an integer number (5866513998).

Almost surely, 223440211411 is an apocalyptic number.

23440211411 is a deficient number, since it is larger than the sum of its proper divisors (25844581).

23440211411 is an equidigital number, since it uses as much as digits as its factorization.

23440211411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25844580.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 23440211411 its reverse (11411204432), we get a palindrome (34851415843).

It can be divided in two parts, 2344021 and 1411, that added together give a palindrome (2345432).

The spelling of 23440211411 in words is "twenty-three billion, four hundred forty million, two hundred eleven thousand, four hundred eleven".

Divisors: 1 907 25843673 23440211411