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2344034113 is a prime number
BaseRepresentation
bin1000101110110111…
…0001111101000001
320001100201021022021
42023231301331001
514300033042423
61024332441441
7112041650461
oct21355617501
96040637267
102344034113
11aa3167583
12555019281
132b4821c45
14183451ba1
15dabbd95d
hex8bb71f41

2344034113 has 2 divisors, whose sum is σ = 2344034114. Its totient is φ = 2344034112.

The previous prime is 2344034071. The next prime is 2344034131. The reversal of 2344034113 is 3114304432.

Together with next prime (2344034131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1628364609 + 715669504 = 40353^2 + 26752^2 .

It is a cyclic number.

It is not a de Polignac number, because 2344034113 - 229 = 1807163201 is a prime.

It is not a weakly prime, because it can be changed into another prime (2344034183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1172017056 + 1172017057.

It is an arithmetic number, because the mean of its divisors is an integer number (1172017057).

Almost surely, 22344034113 is an apocalyptic number.

It is an amenable number.

2344034113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2344034113 is an equidigital number, since it uses as much as digits as its factorization.

2344034113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 25.

The square root of 2344034113 is about 48415.2260451193. The cubic root of 2344034113 is about 1328.3768831077.

Adding to 2344034113 its reverse (3114304432), we get a palindrome (5458338545).

The spelling of 2344034113 in words is "two billion, three hundred forty-four million, thirty-four thousand, one hundred thirteen".