Base | Representation |
---|---|
bin | 1010101010001110101110… |
… | …00001011001111010100011 |
3 | 10001222221221121011122021111 |
4 | 11111013113001121322203 |
5 | 11033030131431112003 |
6 | 121504431524004151 |
7 | 4636400610311440 |
oct | 525072701317243 |
9 | 101887847148244 |
10 | 23441244004003 |
11 | 7518415145831 |
12 | 27670a1230657 |
13 | 1010666164b67 |
14 | 5b07c2bca9c7 |
15 | 2a9b61cd8e6d |
hex | 1551d7059ea3 |
23441244004003 has 4 divisors (see below), whose sum is σ = 26789993147440. Its totient is φ = 20092494860568.
The previous prime is 23441244003979. The next prime is 23441244004019. The reversal of 23441244004003 is 30040044214432.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 23441244004003 - 221 = 23441241906851 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (23441244004033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1674374571708 + ... + 1674374571721.
It is an arithmetic number, because the mean of its divisors is an integer number (6697498286860).
Almost surely, 223441244004003 is an apocalyptic number.
23441244004003 is a deficient number, since it is larger than the sum of its proper divisors (3348749143437).
23441244004003 is an equidigital number, since it uses as much as digits as its factorization.
23441244004003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3348749143436.
The product of its (nonzero) digits is 36864, while the sum is 31.
Adding to 23441244004003 its reverse (30040044214432), we get a palindrome (53481288218435).
The spelling of 23441244004003 in words is "twenty-three trillion, four hundred forty-one billion, two hundred forty-four million, four thousand, three".
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