Base | Representation |
---|---|
bin | 1101101001010010010… |
… | …1101001001110000001 |
3 | 211102002012201021020021 |
4 | 3122110211221032001 |
5 | 12320043302130423 |
6 | 255405214213441 |
7 | 22636113505012 |
oct | 3322445511601 |
9 | 742065637207 |
10 | 234421130113 |
11 | 90465686775 |
12 | 395231b4281 |
13 | 1914b634ba1 |
14 | b4bb785009 |
15 | 61702ac95d |
hex | 3694969381 |
234421130113 has 4 divisors (see below), whose sum is σ = 234430544320. Its totient is φ = 234411715908.
The previous prime is 234421130077. The next prime is 234421130129. The reversal of 234421130113 is 311031124432.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 234421130113 - 221 = 234419032961 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (234421130413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4669653 + ... + 4719586.
It is an arithmetic number, because the mean of its divisors is an integer number (58607636080).
Almost surely, 2234421130113 is an apocalyptic number.
It is an amenable number.
234421130113 is a deficient number, since it is larger than the sum of its proper divisors (9414207).
234421130113 is an equidigital number, since it uses as much as digits as its factorization.
234421130113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9414206.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 234421130113 its reverse (311031124432), we get a palindrome (545452254545).
The spelling of 234421130113 in words is "two hundred thirty-four billion, four hundred twenty-one million, one hundred thirty thousand, one hundred thirteen".
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