Base | Representation |
---|---|
bin | 1101101011000010010… |
… | …1111010100010101101 |
3 | 211110021221210020221122 |
4 | 3122300211322202231 |
5 | 12322024041304432 |
6 | 255524000310325 |
7 | 22653550146356 |
oct | 3326045724255 |
9 | 743257706848 |
10 | 234890963117 |
11 | 90686909208 |
12 | 396346123a5 |
13 | 191c4a86c95 |
14 | b523d26d2d |
15 | 619b667612 |
hex | 36b097a8ad |
234890963117 has 2 divisors, whose sum is σ = 234890963118. Its totient is φ = 234890963116.
The previous prime is 234890963113. The next prime is 234890963213. The reversal of 234890963117 is 711369098432.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 165788223241 + 69102739876 = 407171^2 + 262874^2 .
It is a cyclic number.
It is not a de Polignac number, because 234890963117 - 22 = 234890963113 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (234890963113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 117445481558 + 117445481559.
It is an arithmetic number, because the mean of its divisors is an integer number (117445481559).
Almost surely, 2234890963117 is an apocalyptic number.
It is an amenable number.
234890963117 is a deficient number, since it is larger than the sum of its proper divisors (1).
234890963117 is an equidigital number, since it uses as much as digits as its factorization.
234890963117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1959552, while the sum is 53.
The spelling of 234890963117 in words is "two hundred thirty-four billion, eight hundred ninety million, nine hundred sixty-three thousand, one hundred seventeen".
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