Base | Representation |
---|---|
bin | 100010101100000111101… |
… | …110100010110110001011 |
3 | 22102220002122220220011212 |
4 | 202230013232202312023 |
5 | 303024044120204042 |
6 | 5023041441043335 |
7 | 334140455563406 |
oct | 42540756426613 |
9 | 8386078826155 |
10 | 2383836491147 |
11 | 839a85609801 |
12 | 32600602654b |
13 | 143a4429a897 |
14 | 835420bad3d |
15 | 42020883482 |
hex | 22b07ba2d8b |
2383836491147 has 2 divisors, whose sum is σ = 2383836491148. Its totient is φ = 2383836491146.
The previous prime is 2383836491129. The next prime is 2383836491149. The reversal of 2383836491147 is 7411946383832.
2383836491147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2383836491147 - 26 = 2383836491083 is a prime.
It is a super-3 number, since 3×23838364911473 (a number of 38 digits) contains 333 as substring.
Together with 2383836491149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2383836491149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1191918245573 + 1191918245574.
It is an arithmetic number, because the mean of its divisors is an integer number (1191918245574).
Almost surely, 22383836491147 is an apocalyptic number.
2383836491147 is a deficient number, since it is larger than the sum of its proper divisors (1).
2383836491147 is an equidigital number, since it uses as much as digits as its factorization.
2383836491147 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 20901888, while the sum is 59.
The spelling of 2383836491147 in words is "two trillion, three hundred eighty-three billion, eight hundred thirty-six million, four hundred ninety-one thousand, one hundred forty-seven".
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