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2392861188353 is a prime number
BaseRepresentation
bin100010110100100001101…
…001000010000100000001
322110202101121111000101112
4202310201221002010001
5303201034431011403
65031133143413105
7334610221336106
oct42644151020401
98422347430345
102392861188353
11842896839349
12327904454195
13144851bb72bc
1483b5a8c0aad
154239ccdc9d8
hex22d21a42101

2392861188353 has 2 divisors, whose sum is σ = 2392861188354. Its totient is φ = 2392861188352.

The previous prime is 2392861188343. The next prime is 2392861188371. The reversal of 2392861188353 is 3538811682932.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1977491250289 + 415369938064 = 1406233^2 + 644492^2 .

It is a cyclic number.

It is not a de Polignac number, because 2392861188353 - 212 = 2392861184257 is a prime.

It is a super-2 number, since 2×23928611883532 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2392861188292 and 2392861188301.

It is not a weakly prime, because it can be changed into another prime (2392861188343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1196430594176 + 1196430594177.

It is an arithmetic number, because the mean of its divisors is an integer number (1196430594177).

Almost surely, 22392861188353 is an apocalyptic number.

It is an amenable number.

2392861188353 is a deficient number, since it is larger than the sum of its proper divisors (1).

2392861188353 is an equidigital number, since it uses as much as digits as its factorization.

2392861188353 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 14929920, while the sum is 59.

The spelling of 2392861188353 in words is "two trillion, three hundred ninety-two billion, eight hundred sixty-one million, one hundred eighty-eight thousand, three hundred fifty-three".