Base | Representation |
---|---|
bin | 1101111110000011101… |
… | …1111001100101110101 |
3 | 211221110210200210211202 |
4 | 3133200323321211311 |
5 | 12413003213000203 |
6 | 302130400342245 |
7 | 23224230561416 |
oct | 3374073714565 |
9 | 757423623752 |
10 | 239997000053 |
11 | 92867060348 |
12 | 3a61a614985 |
13 | 19829891105 |
14 | b88a10b80d |
15 | 6399a67388 |
hex | 37e0ef9975 |
239997000053 has 2 divisors, whose sum is σ = 239997000054. Its totient is φ = 239997000052.
The previous prime is 239996999987. The next prime is 239997000091. The reversal of 239997000053 is 350000799932.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 239636683729 + 360316324 = 489527^2 + 18982^2 .
It is a cyclic number.
It is not a de Polignac number, because 239997000053 - 210 = 239996999029 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 239996999971 and 239997000007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (239997600053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 119998500026 + 119998500027.
It is an arithmetic number, because the mean of its divisors is an integer number (119998500027).
Almost surely, 2239997000053 is an apocalyptic number.
It is an amenable number.
239997000053 is a deficient number, since it is larger than the sum of its proper divisors (1).
239997000053 is an equidigital number, since it uses as much as digits as its factorization.
239997000053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 459270, while the sum is 47.
Adding to 239997000053 its reverse (350000799932), we get a palindrome (589997799985).
The spelling of 239997000053 in words is "two hundred thirty-nine billion, nine hundred ninety-seven million, fifty-three", and thus it is an aban number.
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