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240000000041 is a prime number
BaseRepresentation
bin1101111110000100011…
…1010110000000101001
3211221111000100020001102
43133201013112000221
512413010000000131
6302130544531145
723224265224634
oct3374107260051
9757430306042
10240000000041
119286881a27a
123a61b620ab5
131982a3a1759
14b88a68cc1b
156399e5b1cb
hex37e11d6029

240000000041 has 2 divisors, whose sum is σ = 240000000042. Its totient is φ = 240000000040.

The previous prime is 239999999999. The next prime is 240000000103. The reversal of 240000000041 is 140000000042.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 137193196816 + 102806803225 = 370396^2 + 320635^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-240000000041 is a prime.

240000000041 is a modest number, since divided by 41 gives 24 as remainder.

It is not a weakly prime, because it can be changed into another prime (240000000341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120000000020 + 120000000021.

It is an arithmetic number, because the mean of its divisors is an integer number (120000000021).

Almost surely, 2240000000041 is an apocalyptic number.

It is an amenable number.

240000000041 is a deficient number, since it is larger than the sum of its proper divisors (1).

240000000041 is an equidigital number, since it uses as much as digits as its factorization.

240000000041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32, while the sum is 11.

Adding to 240000000041 its reverse (140000000042), we get a palindrome (380000000083).

Subtracting from 240000000041 its reverse (140000000042), we obtain a palindrome (99999999999).

The spelling of 240000000041 in words is "two hundred forty billion, forty-one", and thus it is an aban number.