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24001300117 is a prime number
BaseRepresentation
bin10110010110100101…
…101100011010010101
32021221200200101010101
4112112211230122111
5343123313100432
615005343054101
71506526453624
oct262645543225
967850611111
1024001300117
11a1a7121023
124799ba1331
132356663042
1412398976bb
1595719b4e7
hex59696c695

24001300117 has 2 divisors, whose sum is σ = 24001300118. Its totient is φ = 24001300116.

The previous prime is 24001300091. The next prime is 24001300139. The reversal of 24001300117 is 71100310042.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20402979921 + 3598320196 = 142839^2 + 59986^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-24001300117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 24001300094 and 24001300103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (24001300177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12000650058 + 12000650059.

It is an arithmetic number, because the mean of its divisors is an integer number (12000650059).

Almost surely, 224001300117 is an apocalyptic number.

It is an amenable number.

24001300117 is a deficient number, since it is larger than the sum of its proper divisors (1).

24001300117 is an equidigital number, since it uses as much as digits as its factorization.

24001300117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 168, while the sum is 19.

Adding to 24001300117 its reverse (71100310042), we get a palindrome (95101610159).

The spelling of 24001300117 in words is "twenty-four billion, one million, three hundred thousand, one hundred seventeen".