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240112113 = 3411952131
BaseRepresentation
bin11100100111111…
…01000111110001
3121201210221220020
432103331013301
5442432041423
635454234053
75643630213
oct1623750761
9551727806
10240112113
1111359a86a
12684b5929
133a98cb97
1423c645b3
151612e4e3
hexe4fd1f1

240112113 has 8 divisors (see below), whose sum is σ = 327958176. Its totient is φ = 156170400.

The previous prime is 240112069. The next prime is 240112133. The reversal of 240112113 is 311211042.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 240112113 - 28 = 240111857 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 240112092 and 240112101.

It is not an unprimeable number, because it can be changed into a prime (240112133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 975943 + ... + 976188.

It is an arithmetic number, because the mean of its divisors is an integer number (40994772).

Almost surely, 2240112113 is an apocalyptic number.

It is an amenable number.

240112113 is a deficient number, since it is larger than the sum of its proper divisors (87846063).

240112113 is a wasteful number, since it uses less digits than its factorization.

240112113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1952175.

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 240112113 is about 15495.5513938679. The cubic root of 240112113 is about 621.5432531152.

Adding to 240112113 its reverse (311211042), we get a palindrome (551323155).

The spelling of 240112113 in words is "two hundred forty million, one hundred twelve thousand, one hundred thirteen".

Divisors: 1 3 41 123 1952131 5856393 80037371 240112113