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240305042141113 is a prime number
BaseRepresentation
bin110110101000111001100000…
…101011001010111110111001
31011111211221022120011101221011
4312220321200223022332321
5222444124211242003423
62211030340133313521
7101421315650654605
oct6650714053127671
91144757276141834
10240305042141113
116a628883604994
1222b508884958a1
13a41188c17a0a1
14434ab7cb52505
151cbad43e47b0d
hexda8e60acafb9

240305042141113 has 2 divisors, whose sum is σ = 240305042141114. Its totient is φ = 240305042141112.

The previous prime is 240305042141093. The next prime is 240305042141159. The reversal of 240305042141113 is 311141240503042.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 230476484828304 + 9828557312809 = 15181452^2 + 3135053^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-240305042141113 is a prime.

It is not a weakly prime, because it can be changed into another prime (240305042141183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120152521070556 + 120152521070557.

It is an arithmetic number, because the mean of its divisors is an integer number (120152521070557).

Almost surely, 2240305042141113 is an apocalyptic number.

It is an amenable number.

240305042141113 is a deficient number, since it is larger than the sum of its proper divisors (1).

240305042141113 is an equidigital number, since it uses as much as digits as its factorization.

240305042141113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 240305042141113 its reverse (311141240503042), we get a palindrome (551446282644155).

The spelling of 240305042141113 in words is "two hundred forty trillion, three hundred five billion, forty-two million, one hundred forty-one thousand, one hundred thirteen".