Base | Representation |
---|---|
bin | 110110101001000001111110… |
… | …010111111010010100100111 |
3 | 1011111212210202221012220110201 |
4 | 312221001332113322110213 |
5 | 222444301314331440312 |
6 | 2211034442025131331 |
7 | 101422060114262614 |
oct | 6651017627722447 |
9 | 1144783687186421 |
10 | 240314130343207 |
11 | 6a631717669708 |
12 | 22b525a4029b47 |
13 | a4126a9c9cb6b |
14 | 434b3a1b6750b |
15 | 1cbb1c6c48557 |
hex | da907e5fa527 |
240314130343207 has 2 divisors, whose sum is σ = 240314130343208. Its totient is φ = 240314130343206.
The previous prime is 240314130343187. The next prime is 240314130343297. The reversal of 240314130343207 is 702343031413042.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-240314130343207 is a prime.
It is a super-2 number, since 2×2403141303432072 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (240314130343297) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120157065171603 + 120157065171604.
It is an arithmetic number, because the mean of its divisors is an integer number (120157065171604).
Almost surely, 2240314130343207 is an apocalyptic number.
240314130343207 is a deficient number, since it is larger than the sum of its proper divisors (1).
240314130343207 is an equidigital number, since it uses as much as digits as its factorization.
240314130343207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 145152, while the sum is 37.
Adding to 240314130343207 its reverse (702343031413042), we get a palindrome (942657161756249).
The spelling of 240314130343207 in words is "two hundred forty trillion, three hundred fourteen billion, one hundred thirty million, three hundred forty-three thousand, two hundred seven".
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