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24034135551113 is a prime number
BaseRepresentation
bin1010111011011111000100…
…00111001010110010001001
310011002122022020012212120202
411131233202013022302021
511122233402200113423
6123041043543301545
75030260166311142
oct535574207126211
9104078266185522
1024034135551113
117726901a4a476
122841b8744a8b5
1310545421a630c
145d1388d62ac9
152ba2b2a68728
hex15dbe21cac89

24034135551113 has 2 divisors, whose sum is σ = 24034135551114. Its totient is φ = 24034135551112.

The previous prime is 24034135551067. The next prime is 24034135551203. The reversal of 24034135551113 is 31115553143042.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 23531550970489 + 502584580624 = 4850933^2 + 708932^2 .

It is a cyclic number.

It is not a de Polignac number, because 24034135551113 - 28 = 24034135550857 is a prime.

It is not a weakly prime, because it can be changed into another prime (24034135554113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12017067775556 + 12017067775557.

It is an arithmetic number, because the mean of its divisors is an integer number (12017067775557).

Almost surely, 224034135551113 is an apocalyptic number.

It is an amenable number.

24034135551113 is a deficient number, since it is larger than the sum of its proper divisors (1).

24034135551113 is an equidigital number, since it uses as much as digits as its factorization.

24034135551113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108000, while the sum is 38.

Adding to 24034135551113 its reverse (31115553143042), we get a palindrome (55149688694155).

The spelling of 24034135551113 in words is "twenty-four trillion, thirty-four billion, one hundred thirty-five million, five hundred fifty-one thousand, one hundred thirteen".