Base | Representation |
---|---|
bin | 10110011000111001… |
… | …110010001100101011 |
3 | 2022001101201200112201 |
4 | 112120321302030223 |
5 | 343213232334011 |
6 | 15013251121031 |
7 | 1510510441465 |
oct | 263071621453 |
9 | 68041650481 |
10 | 24040121131 |
11 | a217026904 |
12 | 47aaba3177 |
13 | 2361706060 |
14 | 1240ac1135 |
15 | 95a7b8cc1 |
hex | 598e7232b |
24040121131 has 4 divisors (see below), whose sum is σ = 25889361232. Its totient is φ = 22190881032.
The previous prime is 24040121117. The next prime is 24040121173. The reversal of 24040121131 is 13112104042.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13112104042 = 2 ⋅6556052021.
It is a cyclic number.
It is not a de Polignac number, because 24040121131 - 25 = 24040121099 is a prime.
It is a super-2 number, since 2×240401211312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 24040121099 and 24040121108.
It is not an unprimeable number, because it can be changed into a prime (24040121191) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 924620031 + ... + 924620056.
It is an arithmetic number, because the mean of its divisors is an integer number (6472340308).
Almost surely, 224040121131 is an apocalyptic number.
24040121131 is a deficient number, since it is larger than the sum of its proper divisors (1849240101).
24040121131 is a wasteful number, since it uses less digits than its factorization.
24040121131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1849240100.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 24040121131 its reverse (13112104042), we get a palindrome (37152225173).
The spelling of 24040121131 in words is "twenty-four billion, forty million, one hundred twenty-one thousand, one hundred thirty-one".
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