240653777414113 has 4 divisors (see below), whose sum is σ = 275032888473280. Its totient is φ = 206274666354948.

The previous prime is 240653777414059. The next prime is 240653777414131. The reversal of 240653777414113 is 311414777356042.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 240653777414113 - 2²¹ = 240653775316961 is a prime.

It is not an unprimeable number, because it can be changed into a prime (240653777814113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17189555529573 + ... + 17189555529586.

It is an arithmetic number, because the mean of its divisors is an integer number (68758222118320).

Almost surely, 2^{240653777414113} is an apocalyptic number.

It is an amenable number.

240653777414113 is a deficient number, since it is larger than the sum of its proper divisors (34379111059167).

240653777414113 is an equidigital number, since it uses as much as digits as its factorization.

240653777414113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34379111059166.

The product of its (nonzero) digits is 11854080, while the sum is 55.

The spelling of 240653777414113 in words is "two hundred forty trillion, six hundred fifty-three billion, seven hundred seventy-seven million, four hundred fourteen thousand, one hundred thirteen".