Base | Representation |
---|---|
bin | 110110110011001011001011… |
… | …101111001110010110111011 |
3 | 1011121100110001211020000122122 |
4 | 312303023023233032112323 |
5 | 223042211431012032141 |
6 | 2212331004525511455 |
7 | 101523325351152653 |
oct | 6663131357162673 |
9 | 1147313054200578 |
10 | 241011213002171 |
11 | 6a880310654857 |
12 | 2304570771258b |
13 | a46334bc06cb1 |
14 | 437300d821363 |
15 | 1cce3c4b3864b |
hex | db32cbbce5bb |
241011213002171 has 2 divisors, whose sum is σ = 241011213002172. Its totient is φ = 241011213002170.
The previous prime is 241011213002111. The next prime is 241011213002173. The reversal of 241011213002171 is 171200312110142.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 241011213002171 - 214 = 241011212985787 is a prime.
Together with 241011213002173, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 241011213002171.
It is not a weakly prime, because it can be changed into another prime (241011213002173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120505606501085 + 120505606501086.
It is an arithmetic number, because the mean of its divisors is an integer number (120505606501086).
Almost surely, 2241011213002171 is an apocalyptic number.
241011213002171 is a deficient number, since it is larger than the sum of its proper divisors (1).
241011213002171 is an equidigital number, since it uses as much as digits as its factorization.
241011213002171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 672, while the sum is 26.
The spelling of 241011213002171 in words is "two hundred forty-one trillion, eleven billion, two hundred thirteen million, two thousand, one hundred seventy-one".
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