Base | Representation |
---|---|
bin | 110110110011001100000010… |
… | …011111001101110011000111 |
3 | 1011121100112102211122012202112 |
4 | 312303030002133031303013 |
5 | 223042220321134134310 |
6 | 2212331240021331235 |
7 | 101523360203542064 |
oct | 6663140237156307 |
9 | 1147315384565675 |
10 | 241012131552455 |
11 | 6a8807420a721a |
12 | 23045923266b1b |
13 | a4634672c6c83 |
14 | 4373099809c6b |
15 | 1cce42a5cb705 |
hex | db33027cdcc7 |
241012131552455 has 32 divisors (see below), whose sum is σ = 295004118182400. Its totient is φ = 188970372802432.
The previous prime is 241012131552323. The next prime is 241012131552499. The reversal of 241012131552455 is 554255131210142.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-241012131552455 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 171674417 + ... + 173072613.
It is an arithmetic number, because the mean of its divisors is an integer number (9218878693200).
Almost surely, 2241012131552455 is an apocalyptic number.
241012131552455 is a deficient number, since it is larger than the sum of its proper divisors (53991986629945).
241012131552455 is a wasteful number, since it uses less digits than its factorization.
241012131552455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1400023.
The product of its (nonzero) digits is 240000, while the sum is 41.
Adding to 241012131552455 its reverse (554255131210142), we get a palindrome (795267262762597).
The spelling of 241012131552455 in words is "two hundred forty-one trillion, twelve billion, one hundred thirty-one million, five hundred fifty-two thousand, four hundred fifty-five".
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