Base | Representation |
---|---|
bin | 100011000101011011100… |
… | …001011001000101011101 |
3 | 22112111020120200112211120 |
4 | 203011123201121011131 |
5 | 304000223101230323 |
6 | 5043334221241153 |
7 | 336122061664515 |
oct | 43053341310535 |
9 | 8474216615746 |
10 | 2411012133213 |
11 | 84a560548922 |
12 | 32b32b1031b9 |
13 | 146485487868 |
14 | 8499d3a0845 |
15 | 42ab15605e3 |
hex | 2315b85915d |
2411012133213 has 4 divisors (see below), whose sum is σ = 3214682844288. Its totient is φ = 1607341422140.
The previous prime is 2411012133203. The next prime is 2411012133239. The reversal of 2411012133213 is 3123312101142.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2411012133213 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2411012133203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 401835355533 + ... + 401835355538.
It is an arithmetic number, because the mean of its divisors is an integer number (803670711072).
Almost surely, 22411012133213 is an apocalyptic number.
It is an amenable number.
2411012133213 is a deficient number, since it is larger than the sum of its proper divisors (803670711075).
2411012133213 is an equidigital number, since it uses as much as digits as its factorization.
2411012133213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 803670711074.
The product of its (nonzero) digits is 864, while the sum is 24.
Adding to 2411012133213 its reverse (3123312101142), we get a palindrome (5534324234355).
The spelling of 2411012133213 in words is "two trillion, four hundred eleven billion, twelve million, one hundred thirty-three thousand, two hundred thirteen".
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