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241122414102539 is a prime number
BaseRepresentation
bin110110110100110010101111…
…110101110000100000001011
31011121202002002121201012222112
4312310302233311300200023
5223101022201002240124
62212454035143212535
7101534343126003524
oct6664625765604013
91147662077635875
10241122414102539
116a9134947923a2
122306318074714b
13a4709911c2178
14437855c33d84b
151cd22323d790e
hexdb4cafd7080b

241122414102539 has 2 divisors, whose sum is σ = 241122414102540. Its totient is φ = 241122414102538.

The previous prime is 241122414102509. The next prime is 241122414102541. The reversal of 241122414102539 is 935201414221142.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-241122414102539 is a prime.

Together with 241122414102541, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 241122414102496 and 241122414102505.

It is not a weakly prime, because it can be changed into another prime (241122414102509) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120561207051269 + 120561207051270.

It is an arithmetic number, because the mean of its divisors is an integer number (120561207051270).

Almost surely, 2241122414102539 is an apocalyptic number.

241122414102539 is a deficient number, since it is larger than the sum of its proper divisors (1).

241122414102539 is an equidigital number, since it uses as much as digits as its factorization.

241122414102539 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 138240, while the sum is 41.

The spelling of 241122414102539 in words is "two hundred forty-one trillion, one hundred twenty-two billion, four hundred fourteen million, one hundred two thousand, five hundred thirty-nine".