Base | Representation |
---|---|
bin | 100011000110011101101… |
… | …011010001110111011101 |
3 | 22112121002221010201010021 |
4 | 203012131223101313131 |
5 | 304010011214140331 |
6 | 5044040310112141 |
7 | 336161426613124 |
oct | 43063553216735 |
9 | 8477087121107 |
10 | 2412122021341 |
11 | 84aa7aaa723a |
12 | 32b59a94b651 |
13 | 1466013bb1b6 |
14 | 84a66954abb |
15 | 42b28beb211 |
hex | 2319dad1ddd |
2412122021341 has 2 divisors, whose sum is σ = 2412122021342. Its totient is φ = 2412122021340.
The previous prime is 2412122021321. The next prime is 2412122021443. The reversal of 2412122021341 is 1431202212142.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2063259324025 + 348862697316 = 1436405^2 + 590646^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2412122021341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2412122021321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1206061010670 + 1206061010671.
It is an arithmetic number, because the mean of its divisors is an integer number (1206061010671).
Almost surely, 22412122021341 is an apocalyptic number.
It is an amenable number.
2412122021341 is a deficient number, since it is larger than the sum of its proper divisors (1).
2412122021341 is an equidigital number, since it uses as much as digits as its factorization.
2412122021341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 2412122021341 its reverse (1431202212142), we get a palindrome (3843324233483).
The spelling of 2412122021341 in words is "two trillion, four hundred twelve billion, one hundred twenty-two million, twenty-one thousand, three hundred forty-one".
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