Base | Representation |
---|---|
bin | 110110110110001101111100… |
… | …010001001010101010111111 |
3 | 1011122002102211202121201002221 |
4 | 312312031330101022222333 |
5 | 223104123220234321231 |
6 | 2213011031411430211 |
7 | 101544410503633225 |
oct | 6666157421125277 |
9 | 1148072752551087 |
10 | 241220333120191 |
11 | 6a950a72499677 |
12 | 2307a1495b5367 |
13 | a479c97841cb9 |
14 | 437d1aac64b15 |
15 | 1cd4a63ab4d11 |
hex | db637c44aabf |
241220333120191 has 2 divisors, whose sum is σ = 241220333120192. Its totient is φ = 241220333120190.
The previous prime is 241220333120113. The next prime is 241220333120219. The reversal of 241220333120191 is 191021333022142.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-241220333120191 is a prime.
It is a super-2 number, since 2×2412203331201912 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (241220333120791) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120610166560095 + 120610166560096.
It is an arithmetic number, because the mean of its divisors is an integer number (120610166560096).
Almost surely, 2241220333120191 is an apocalyptic number.
241220333120191 is a deficient number, since it is larger than the sum of its proper divisors (1).
241220333120191 is an equidigital number, since it uses as much as digits as its factorization.
241220333120191 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 34.
The spelling of 241220333120191 in words is "two hundred forty-one trillion, two hundred twenty billion, three hundred thirty-three million, one hundred twenty thousand, one hundred ninety-one".
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