Base | Representation |
---|---|
bin | 110110110110100010011100… |
… | …110001100001101101010111 |
3 | 1011122011112200101111021112212 |
4 | 312312202130301201231113 |
5 | 223110003314421414201 |
6 | 2213025112424504035 |
7 | 101546120256313025 |
oct | 6666423461415527 |
9 | 1148145611437485 |
10 | 241242353310551 |
11 | 6a95a3422a55aa |
12 | 2308247401b01b |
13 | a47c096912c38 |
14 | 438029957d715 |
15 | 1cd5401d80abb |
hex | db689cc61b57 |
241242353310551 has 2 divisors, whose sum is σ = 241242353310552. Its totient is φ = 241242353310550.
The previous prime is 241242353310499. The next prime is 241242353310577. The reversal of 241242353310551 is 155013353242142.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 241242353310551 - 210 = 241242353309527 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 241242353310499 and 241242353310508.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (241242350310551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120621176655275 + 120621176655276.
It is an arithmetic number, because the mean of its divisors is an integer number (120621176655276).
Almost surely, 2241242353310551 is an apocalyptic number.
241242353310551 is a deficient number, since it is larger than the sum of its proper divisors (1).
241242353310551 is an equidigital number, since it uses as much as digits as its factorization.
241242353310551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432000, while the sum is 41.
The spelling of 241242353310551 in words is "two hundred forty-one trillion, two hundred forty-two billion, three hundred fifty-three million, three hundred ten thousand, five hundred fifty-one".
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