Base | Representation |
---|---|
bin | 100011000111010010000… |
… | …101100111010010010111 |
3 | 22112200101012201201122001 |
4 | 203013102011213102113 |
5 | 304013311320340210 |
6 | 5044303441020131 |
7 | 336222264654415 |
oct | 43072205472227 |
9 | 8480335651561 |
10 | 2413001340055 |
11 | 850391393419 |
12 | 32b7a5324647 |
13 | 146711623327 |
14 | 84b0b64a2b5 |
15 | 42b7aee003a |
hex | 231d2167497 |
2413001340055 has 16 divisors (see below), whose sum is σ = 2992895136000. Its totient is φ = 1865700679680.
The previous prime is 2413001340047. The next prime is 2413001340067. The reversal of 2413001340055 is 5500431003142.
It is not a de Polignac number, because 2413001340055 - 23 = 2413001340047 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10002880 + ... + 10241269.
It is an arithmetic number, because the mean of its divisors is an integer number (187055946000).
Almost surely, 22413001340055 is an apocalyptic number.
2413001340055 is a deficient number, since it is larger than the sum of its proper divisors (579893795945).
2413001340055 is a wasteful number, since it uses less digits than its factorization.
2413001340055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20244954.
The product of its (nonzero) digits is 7200, while the sum is 28.
Adding to 2413001340055 its reverse (5500431003142), we get a palindrome (7913432343197).
The spelling of 2413001340055 in words is "two trillion, four hundred thirteen billion, one million, three hundred forty thousand, fifty-five".
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