Base | Representation |
---|---|
bin | 110110110111100100011000… |
… | …111010000111100100011101 |
3 | 1011122102022102201010210220202 |
4 | 312313210120322013210131 |
5 | 223112133320241224201 |
6 | 2213121422211353245 |
7 | 101554204643260415 |
oct | 6667443072074435 |
9 | 1148368381123822 |
10 | 241313155414301 |
11 | 6a987375235033 |
12 | 230941335b2825 |
13 | a48596b298b99 |
14 | 438389490b645 |
15 | 1cd7197ad1c6b |
hex | db7918e8791d |
241313155414301 has 2 divisors, whose sum is σ = 241313155414302. Its totient is φ = 241313155414300.
The previous prime is 241313155414273. The next prime is 241313155414307. The reversal of 241313155414301 is 103414551313142.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 207145927279225 + 34167228135076 = 14392565^2 + 5845274^2 .
It is a cyclic number.
It is not a de Polignac number, because 241313155414301 - 226 = 241313088305437 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (241313155414307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120656577707150 + 120656577707151.
It is an arithmetic number, because the mean of its divisors is an integer number (120656577707151).
Almost surely, 2241313155414301 is an apocalyptic number.
It is an amenable number.
241313155414301 is a deficient number, since it is larger than the sum of its proper divisors (1).
241313155414301 is an equidigital number, since it uses as much as digits as its factorization.
241313155414301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 38.
The spelling of 241313155414301 in words is "two hundred forty-one trillion, three hundred thirteen billion, one hundred fifty-five million, four hundred fourteen thousand, three hundred one".
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