Base | Representation |
---|---|
bin | 110110110111100100011100… |
… | …111010000100111100110001 |
3 | 1011122102022121101101202020202 |
4 | 312313210130322010330301 |
5 | 223112133434430344213 |
6 | 2213121433005444545 |
7 | 101554206416506661 |
oct | 6667443472047461 |
9 | 1148368541352222 |
10 | 241313222512433 |
11 | 6a9873aa0a3935 |
12 | 23094151b70755 |
13 | a48597c15c916 |
14 | 438389d7b61a1 |
15 | 1cd719d937b58 |
hex | db791ce84f31 |
241313222512433 has 64 divisors (see below), whose sum is σ = 274698202521600. Its totient is φ = 210747507505920.
The previous prime is 241313222512429. The next prime is 241313222512601. The reversal of 241313222512433 is 334215222313142.
It is a cyclic number.
It is not a de Polignac number, because 241313222512433 - 22 = 241313222512429 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (241313222512133) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 22403970338 + ... + 22403981108.
It is an arithmetic number, because the mean of its divisors is an integer number (4292159414400).
Almost surely, 2241313222512433 is an apocalyptic number.
241313222512433 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
It is an amenable number.
241313222512433 is a deficient number, since it is larger than the sum of its proper divisors (33384980009167).
241313222512433 is a wasteful number, since it uses less digits than its factorization.
241313222512433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13902.
The product of its digits is 207360, while the sum is 38.
Adding to 241313222512433 its reverse (334215222313142), we get a palindrome (575528444825575).
The spelling of 241313222512433 in words is "two hundred forty-one trillion, three hundred thirteen billion, two hundred twenty-two million, five hundred twelve thousand, four hundred thirty-three".
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