Search a number
-
+
2413140413143 = 2818587688303
BaseRepresentation
bin100011000111011010011…
…000001000101011010111
322112200201220102101001011
4203013122120020223113
5304014102421210033
65044325325513051
7336225604034335
oct43073230105327
98480656371034
102413140413143
11850452942059
1232b823a12787
131467343977b5
1484b21cccb55
1542b88311ccd
hex231da608ad7

2413140413143 has 4 divisors (see below), whose sum is σ = 2421728101728. Its totient is φ = 2404552724560.

The previous prime is 2413140413129. The next prime is 2413140413213. The reversal of 2413140413143 is 3413140413142.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2413140413143 - 241 = 214117157591 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2413140413443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4293843871 + ... + 4293844432.

It is an arithmetic number, because the mean of its divisors is an integer number (605432025432).

Almost surely, 22413140413143 is an apocalyptic number.

2413140413143 is a deficient number, since it is larger than the sum of its proper divisors (8587688585).

2413140413143 is an equidigital number, since it uses as much as digits as its factorization.

2413140413143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8587688584.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 2413140413143 its reverse (3413140413142), we get a palindrome (5826280826285).

Subtracting 2413140413143 from its reverse (3413140413142), we obtain a palindrome (999999999999).

The spelling of 2413140413143 in words is "two trillion, four hundred thirteen billion, one hundred forty million, four hundred thirteen thousand, one hundred forty-three".

Divisors: 1 281 8587688303 2413140413143