241314321311143 has 8 divisors (see below), whose sum is σ = 243054360001040. Its totient is φ = 239574339256320.

The previous prime is 241314321311111. The next prime is 241314321311153. The reversal of 241314321311143 is 341113123413142.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 241314321311143 - 2⁵ = 241314321311111 is a prime.

It is a super-3 number, since 3×241314321311143³ (a number of 44 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 241314321311099 and 241314321311108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (241314321311153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5587680 + ... + 22668277.

It is an arithmetic number, because the mean of its divisors is an integer number (30381795000130).

Almost surely, 2^{241314321311143} is an apocalyptic number.

241314321311143 is a deficient number, since it is larger than the sum of its proper divisors (1740038689897).

241314321311143 is a wasteful number, since it uses less digits than its factorization.

241314321311143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28317537.

The product of its digits is 20736, while the sum is 34.

Adding to 241314321311143 its reverse (341113123413142), we get a palindrome (582427444724285).

The spelling of 241314321311143 in words is "two hundred forty-one trillion, three hundred fourteen billion, three hundred twenty-one million, three hundred eleven thousand, one hundred forty-three".