2413200000041 has 2 divisors, whose sum is σ = 2413200000042. Its totient is φ = 2413200000040.

The previous prime is 2413200000011. The next prime is 2413200000053. The reversal of 2413200000041 is 1400000023142.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2223543234025 + 189656766016 = 1491155^2 + 435496^2 .

It is a cyclic number.

It is not a de Polignac number, because 2413200000041 - 2¹⁴ = 2413199983657 is a prime.

It is a zygodrome in base 3.

It is a junction number, because it is equal to n+sod(n) for n = 2413199999965 and 2413200000019.

It is not a weakly prime, because it can be changed into another prime (2413200000011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1206600000020 + 1206600000021.

It is an arithmetic number, because the mean of its divisors is an integer number (1206600000021).

Almost surely, 2^{2413200000041} is an apocalyptic number.

It is an amenable number.

2413200000041 is a deficient number, since it is larger than the sum of its proper divisors (1).

2413200000041 is an equidigital number, since it uses as much as digits as its factorization.

2413200000041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 17.

Adding to 2413200000041 its reverse (1400000023142), we get a palindrome (3813200023183).

The spelling of 2413200000041 in words is "two trillion, four hundred thirteen billion, two hundred million, forty-one", and thus it is an aban number.