Base | Representation |
---|---|
bin | 1010111110010101011001… |
… | …00111110111100100100001 |
3 | 10011102222222010121002021001 |
4 | 11133022230213313210201 |
5 | 11130334340213320223 |
6 | 123154033102232001 |
7 | 5040324003644101 |
oct | 537125447674441 |
9 | 104388863532231 |
10 | 24132022401313 |
11 | 7764373585882 |
12 | 2858b45585601 |
13 | 1060841c72758 |
14 | 5d5dd34b3201 |
15 | 2bcae14de9ad |
hex | 15f2ac9f7921 |
24132022401313 has 6 divisors (see below), whose sum is σ = 25635054938726. Its totient is φ = 22712491671552.
The previous prime is 24132022401281. The next prime is 24132022401349. The reversal of 24132022401313 is 31310422023142.
It can be written as a sum of positive squares in 3 ways, for example, as 12481862889024 + 11650159512289 = 3532968^2 + 3413233^2 .
It is not a de Polignac number, because 24132022401313 - 25 = 24132022401281 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (24132022401713) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 41750903520 + ... + 41750904097.
Almost surely, 224132022401313 is an apocalyptic number.
It is an amenable number.
24132022401313 is a deficient number, since it is larger than the sum of its proper divisors (1503032537413).
24132022401313 is an equidigital number, since it uses as much as digits as its factorization.
24132022401313 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 83501807651 (or 83501807634 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 24132022401313 its reverse (31310422023142), we get a palindrome (55442444424455).
The spelling of 24132022401313 in words is "twenty-four trillion, one hundred thirty-two billion, twenty-two million, four hundred one thousand, three hundred thirteen".
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