2413232540333 has 4 divisors (see below), whose sum is σ = 2422137457728. Its totient is φ = 2404327622940.

The previous prime is 2413232540273. The next prime is 2413232540371. The reversal of 2413232540333 is 3330452323142.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2413232540333 - 2¹⁶ = 2413232474797 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2413232540293 and 2413232540302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2413232740333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4452458291 + ... + 4452458832.

It is an arithmetic number, because the mean of its divisors is an integer number (605534364432).

Almost surely, 2^{2413232540333} is an apocalyptic number.

It is an amenable number.

2413232540333 is a deficient number, since it is larger than the sum of its proper divisors (8904917395).

2413232540333 is an equidigital number, since it uses as much as digits as its factorization.

2413232540333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8904917394.

The product of its (nonzero) digits is 155520, while the sum is 35.

Adding to 2413232540333 its reverse (3330452323142), we get a palindrome (5743684863475).

The spelling of 2413232540333 in words is "two trillion, four hundred thirteen billion, two hundred thirty-two million, five hundred forty thousand, three hundred thirty-three".