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24134134312133 is a prime number
BaseRepresentation
bin1010111110011001010101…
…00000001010110011000101
310011110012102022112021021022
411133030222200022303011
511130403201340442013
6123155022424000525
75040430226616356
oct537145240126305
9104405368467238
1024134134312133
11776525770971a
122859434900145
131060aba670b21
145d6153b7dd2d
152bcbb6b0b008
hex15f32a80acc5

24134134312133 has 2 divisors, whose sum is σ = 24134134312134. Its totient is φ = 24134134312132.

The previous prime is 24134134312117. The next prime is 24134134312159. The reversal of 24134134312133 is 33121343143142.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 22281968462884 + 1852165849249 = 4720378^2 + 1360943^2 .

It is a cyclic number.

It is not a de Polignac number, because 24134134312133 - 24 = 24134134312117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 24134134312093 and 24134134312102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (24134134312103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12067067156066 + 12067067156067.

It is an arithmetic number, because the mean of its divisors is an integer number (12067067156067).

Almost surely, 224134134312133 is an apocalyptic number.

It is an amenable number.

24134134312133 is a deficient number, since it is larger than the sum of its proper divisors (1).

24134134312133 is an equidigital number, since it uses as much as digits as its factorization.

24134134312133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 62208, while the sum is 35.

Adding to 24134134312133 its reverse (33121343143142), we get a palindrome (57255477455275).

The spelling of 24134134312133 in words is "twenty-four trillion, one hundred thirty-four billion, one hundred thirty-four million, three hundred twelve thousand, one hundred thirty-three".