2413433131 has 2 divisors, whose sum is σ = 2413433132. Its totient is φ = 2413433130.

The previous prime is 2413433129. The next prime is 2413433153. The reversal of 2413433131 is 1313343142.

2413433131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2413433131 - 2¹ = 2413433129 is a prime.

It is a super-2 number, since 2×2413433131² = 11649318955616926322, which contains 22 as substring.

Together with 2413433129, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 2413433096 and 2413433105.

It is not a weakly prime, because it can be changed into another prime (2413433161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1206716565 + 1206716566.

It is an arithmetic number, because the mean of its divisors is an integer number (1206716566).

Almost surely, 2^2413433131 is an apocalyptic number.

2413433131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2413433131 is an equidigital number, since it uses as much as digits as its factorization.

2413433131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2592, while the sum is 25.

The square root of 2413433131 is about 49126.7048660909. The cubic root of 2413433131 is about 1341.3591931975.

Adding to 2413433131 its reverse (1313343142), we get a palindrome (3726776273).

The spelling of 2413433131 in words is "two billion, four hundred thirteen million, four hundred thirty-three thousand, one hundred thirty-one".