Base | Representation |
---|---|
bin | 1110000011000100111… |
… | …0010110010110001111 |
3 | 212001221200100012012111 |
4 | 3200301032112112033 |
5 | 12423233031414321 |
6 | 302512155444451 |
7 | 23302505161063 |
oct | 3406116262617 |
9 | 761850305174 |
10 | 241344013711 |
11 | 93398449679 |
12 | 3a935756727 |
13 | 199b297a108 |
14 | b976d89aa3 |
15 | 6427e425e1 |
hex | 383139658f |
241344013711 has 2 divisors, whose sum is σ = 241344013712. Its totient is φ = 241344013710.
The previous prime is 241344013657. The next prime is 241344013733. The reversal of 241344013711 is 117310443142.
241344013711 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 241344013711 - 27 = 241344013583 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (241344019711) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120672006855 + 120672006856.
It is an arithmetic number, because the mean of its divisors is an integer number (120672006856).
Almost surely, 2241344013711 is an apocalyptic number.
241344013711 is a deficient number, since it is larger than the sum of its proper divisors (1).
241344013711 is an equidigital number, since it uses as much as digits as its factorization.
241344013711 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8064, while the sum is 31.
Adding to 241344013711 its reverse (117310443142), we get a palindrome (358654456853).
The spelling of 241344013711 in words is "two hundred forty-one billion, three hundred forty-four million, thirteen thousand, seven hundred eleven".
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