Base | Representation |
---|---|
bin | 1010111110011011100101… |
… | …01000000110111101000101 |
3 | 10011110022112122102201102011 |
4 | 11133031302220012331011 |
5 | 11130413141123244333 |
6 | 123155342451214221 |
7 | 5040502222034521 |
oct | 537156250067505 |
9 | 104408478381364 |
10 | 24135344353093 |
11 | 7765818753376 |
12 | 2859711ba7371 |
13 | 1060c5126c6ac |
14 | 5d622a764d81 |
15 | 2bcc37e7b9cd |
hex | 15f372a06f45 |
24135344353093 has 2 divisors, whose sum is σ = 24135344353094. Its totient is φ = 24135344353092.
The previous prime is 24135344353019. The next prime is 24135344353121. The reversal of 24135344353093 is 39035344353142.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 23704113103969 + 431231249124 = 4868687^2 + 656682^2 .
It is a cyclic number.
It is not a de Polignac number, because 24135344353093 - 213 = 24135344344901 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (24135344353013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12067672176546 + 12067672176547.
It is an arithmetic number, because the mean of its divisors is an integer number (12067672176547).
Almost surely, 224135344353093 is an apocalyptic number.
It is an amenable number.
24135344353093 is a deficient number, since it is larger than the sum of its proper divisors (1).
24135344353093 is an equidigital number, since it uses as much as digits as its factorization.
24135344353093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6998400, while the sum is 49.
Adding to 24135344353093 its sum of digits (49), we get a palindrome (24135344353142).
The spelling of 24135344353093 in words is "twenty-four trillion, one hundred thirty-five billion, three hundred forty-four million, three hundred fifty-three thousand, ninety-three".
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