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241412201326333 is a prime number
BaseRepresentation
bin110110111001000000101000…
…100000010010011011111101
31011122202210002101111110112001
4312321000220200102123331
5223120244142014420313
62213235122333142301
7101564312253525352
oct6671005040223375
91148683071443461
10241412201326333
116aa15381055784
12230ab37592a991
13a4920c4224c1b
1443885acd72629
151cd9a431a8add
hexdb90288126fd

241412201326333 has 2 divisors, whose sum is σ = 241412201326334. Its totient is φ = 241412201326332.

The previous prime is 241412201326277. The next prime is 241412201326367. The reversal of 241412201326333 is 333623102214142.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 238331288232324 + 3080913094009 = 15437982^2 + 1755253^2 .

It is a cyclic number.

It is not a de Polignac number, because 241412201326333 - 233 = 241403611391741 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 241412201326292 and 241412201326301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (241412201326433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120706100663166 + 120706100663167.

It is an arithmetic number, because the mean of its divisors is an integer number (120706100663167).

Almost surely, 2241412201326333 is an apocalyptic number.

It is an amenable number.

241412201326333 is a deficient number, since it is larger than the sum of its proper divisors (1).

241412201326333 is an equidigital number, since it uses as much as digits as its factorization.

241412201326333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 124416, while the sum is 37.

The spelling of 241412201326333 in words is "two hundred forty-one trillion, four hundred twelve billion, two hundred one million, three hundred twenty-six thousand, three hundred thirty-three".