Base | Representation |
---|---|
bin | 1110000011010111000… |
… | …1110111101011010101 |
3 | 212002011000010202022111 |
4 | 3200311301313223111 |
5 | 12423412112343013 |
6 | 302523525431021 |
7 | 23304423555124 |
oct | 3406561675325 |
9 | 762130122274 |
10 | 241420434133 |
11 | 934275a544a |
12 | 3a95726b471 |
13 | 199c57560b8 |
14 | b98319dabb |
15 | 642e9da73d |
hex | 3835c77ad5 |
241420434133 has 2 divisors, whose sum is σ = 241420434134. Its totient is φ = 241420434132.
The previous prime is 241420434113. The next prime is 241420434169. The reversal of 241420434133 is 331434024142.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 122159337169 + 119261096964 = 349513^2 + 345342^2 .
It is a cyclic number.
It is not a de Polignac number, because 241420434133 - 237 = 103981480661 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 241420434095 and 241420434104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (241420434113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120710217066 + 120710217067.
It is an arithmetic number, because the mean of its divisors is an integer number (120710217067).
Almost surely, 2241420434133 is an apocalyptic number.
It is an amenable number.
241420434133 is a deficient number, since it is larger than the sum of its proper divisors (1).
241420434133 is an equidigital number, since it uses as much as digits as its factorization.
241420434133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 241420434133 its reverse (331434024142), we get a palindrome (572854458275).
The spelling of 241420434133 in words is "two hundred forty-one billion, four hundred twenty million, four hundred thirty-four thousand, one hundred thirty-three".
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