Base | Representation |
---|---|
bin | 110110111001001100010010… |
… | …001110110111111010110011 |
3 | 1011122210222101022121012122211 |
4 | 312321030102032313322303 |
5 | 223121000302404030103 |
6 | 2213244552024312551 |
7 | 101565234303353164 |
oct | 6671142216677263 |
9 | 1148728338535584 |
10 | 241424712564403 |
11 | 6aa1a71134a055 |
12 | 230b1887912757 |
13 | a493339277a84 |
14 | 438903882d76b |
15 | 1cda02676236d |
hex | db93123b7eb3 |
241424712564403 has 8 divisors (see below), whose sum is σ = 255732988755888. Its totient is φ = 227128305540864.
The previous prime is 241424712564337. The next prime is 241424712564479. The reversal of 241424712564403 is 304465217424142.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 241424712564403 - 213 = 241424712556211 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (241424712564493) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2967250101 + ... + 2967331462.
It is an arithmetic number, because the mean of its divisors is an integer number (31966623594486).
Almost surely, 2241424712564403 is an apocalyptic number.
241424712564403 is a deficient number, since it is larger than the sum of its proper divisors (14308276191485).
241424712564403 is a wasteful number, since it uses less digits than its factorization.
241424712564403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5934583973.
The product of its (nonzero) digits is 5160960, while the sum is 49.
Adding to 241424712564403 its reverse (304465217424142), we get a palindrome (545889929988545).
The spelling of 241424712564403 in words is "two hundred forty-one trillion, four hundred twenty-four billion, seven hundred twelve million, five hundred sixty-four thousand, four hundred three".
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