Base | Representation |
---|---|
bin | 110110111001001101000001… |
… | …111110010100001011100111 |
3 | 1011122211001110010202111000112 |
4 | 312321031001332110023213 |
5 | 223121003422430430322 |
6 | 2213245203320003235 |
7 | 101565263200431125 |
oct | 6671150176241347 |
9 | 1148731403674015 |
10 | 241425513530087 |
11 | 6aa1aa9248a467 |
12 | 230b1a7000051b |
13 | a4934361a8373 |
14 | 43890b2d6a915 |
15 | 1cda071c2a5e2 |
hex | db9341f942e7 |
241425513530087 has 2 divisors, whose sum is σ = 241425513530088. Its totient is φ = 241425513530086.
The previous prime is 241425513530081. The next prime is 241425513530167. The reversal of 241425513530087 is 780035315524142.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-241425513530087 is a prime.
It is a super-2 number, since 2×2414255135300872 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (241425513530081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120712756765043 + 120712756765044.
It is an arithmetic number, because the mean of its divisors is an integer number (120712756765044).
Almost surely, 2241425513530087 is an apocalyptic number.
241425513530087 is a deficient number, since it is larger than the sum of its proper divisors (1).
241425513530087 is an equidigital number, since it uses as much as digits as its factorization.
241425513530087 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032000, while the sum is 50.
The spelling of 241425513530087 in words is "two hundred forty-one trillion, four hundred twenty-five billion, five hundred thirteen million, five hundred thirty thousand, eighty-seven".
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