Base | Representation |
---|---|
bin | 110110111001010010010111… |
… | …010011011101010011000111 |
3 | 1011122211121020020022112101201 |
4 | 312321102113103131103013 |
5 | 223121102134431244421 |
6 | 2213251551444203331 |
7 | 101565555124463242 |
oct | 6671222723352307 |
9 | 1148747206275351 |
10 | 241431240103111 |
11 | 6aa22460a36543 |
12 | 230b2ba9999547 |
13 | a493b3971b506 |
14 | 4389497722259 |
15 | 1cda2a9852b91 |
hex | db94974dd4c7 |
241431240103111 has 2 divisors, whose sum is σ = 241431240103112. Its totient is φ = 241431240103110.
The previous prime is 241431240103051. The next prime is 241431240103127. The reversal of 241431240103111 is 111301042134142.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-241431240103111 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 241431240103111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (241431240103411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120715620051555 + 120715620051556.
It is an arithmetic number, because the mean of its divisors is an integer number (120715620051556).
Almost surely, 2241431240103111 is an apocalyptic number.
241431240103111 is a deficient number, since it is larger than the sum of its proper divisors (1).
241431240103111 is an equidigital number, since it uses as much as digits as its factorization.
241431240103111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 241431240103111 its reverse (111301042134142), we get a palindrome (352732282237253).
The spelling of 241431240103111 in words is "two hundred forty-one trillion, four hundred thirty-one billion, two hundred forty million, one hundred three thousand, one hundred eleven".
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